Respuesta :

[tex]\\ \tt\hookrightarrow \dfrac{(3\times 10^4kg)(4\times 10^4m)}{6\times 10^4s)}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{12\times 10^8kgm}{6\times 10^4s}[/tex]

[tex]\\ \tt\hookrightarrow 2kgm/s[/tex]

We have calculated momentum