keyjones129
contestada

6+2/3b=3/4b-4
smallest common multiple of 3 and 4 is 12
72+8b=9b-48?
_-72______-72_
8b=9b-120

What are my next steps and what are my mistakes?

Respuesta :

​Answer:

b=120

Step-by-step explanation:

Solve for b by simplifying both sides of the equation, then isolating the variable.

1) Subtract 3/4b from both sides.

6+ 2/3b− 3/4b = -4

2) Combine 2/3b and -3/4b to get -1/12b

3) Subtract 6 from both sides

6-6-1/12b

4) subtract 6 from -4 to get -10

-1/12b = -10

5) multiply both sides by -12 (the reciprocal of -1/12)

b= -10(-12)

6) multiply -10(-12) to get 120

b=120

affanahmed2929

Answer:

b=120

Step-by-step explanation:

Solve for b by simplifying both sides of the equation, then isolating the variable.

1) Subtract 3/4b from both sides.

6+ 2/3b− 3/4b = -4

2) Combine 2/3b and -3/4b to get -1/12b

3) Subtract 6 from both sides

6-6-1/12b

4) subtract 6 from -4 to get -10

-1/12b = -10

5) multiply both sides by -12 (the reciprocal of -1/12)

b= -10(-12)

6) multiply -10(-12) to get 120

b=120

Step-by-step explanation:

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