(a) The tangential speed of the discus at the release is 15 m/s.
(b) The centripetal acceleration of the discus is 225 m/s².
(c) The centripetal force on the discus is 360 N.
The given parameters;
- mass of the discus, m = 1.6 kg
- radius of the path, r = 1 m
- angular speed, ω = 15 rad/s
- time of motion, t = 1.2 s
The tangential speed of the discus at the release is calculated as follows;
[tex]v = \omega r\\\\v = 15 \ rad/s \ \times 1 \ m\\\\v = 15 \ m/s[/tex]
The centripetal acceleration of the discus is calculated as follows;
[tex]a_c = \frac{v^2}{r} \\\\a_c = \frac{15^2}{1} \\\\a _c = 225 \ m/s^2[/tex]
The centripetal force on the discus is calculated as follows;
[tex]F_c = ma_c\\\\F_c = 1.6 \times 225\\\\F_c = 360 \ N[/tex]
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