A student is participating in the hammer throw. The student rotates in uniform circular motion with the mass rotation 2.3 m away from the center of rotation. Refer to the information and diagram shown above. The student athlete can rotate so that the
object is moving with a speed of 10 m/s.
A. Calculate the acceleration necessary to maintain uniform circular motion.
B. If the length of the chain is increased, doubling the distance from the athlete to the
mass, By what factor will the acceleration of the ball change if the speed remains
unchanged?
C. The net force that causes the centripetal acceleration of an object in a circular motion is the_?
D. What happens to the centripetal acceleration of the ball if its mass is doubled?

The centripetal acceleration relations and Newton's second law we can find the results for the questions about the change in centripetal acceleration when changing the conditions of motion are:

A. The centripetal acceleration is: a = 43.5 m / s²

B. The radius is doubled, the centripetal acceleration is halved.

C. The force that creates the movement is called the centripetal force.

D. If the mass is doubled, the centripetal acceleration is halved.

Kinematics studies the motion of bodies, in the case of rotational motion, it looks for relationships between the angle, the angular velocity and the angular acceleration.

The centripetal acceleration of the body is

a = [tex]\frac{v^2 }{r}[/tex]

A. Indicate the velocity of the body v = 10 m/s and the radius of the circle r=2.30 m. Let's calculate the centripetal acceleration is:

a = [tex]\frac{10^2}{2.3}[/tex]

a = 43.5 m / s²

B. The radius is doubled, ask the change in acceleration

r₂ = 2 r₀

a₂ = [tex]\frac{v^2}{r_2}[/tex]

a₂ = [tex]\frac{v^2}{2 r_o}[/tex]

a₂ = ½ a₀

[tex]\frac{a_2}{a_o} = \frac{1}{2}[/tex]

Let's calculate

a₂ = ½ 43.5

a₂ = 21.75 m / s²

C. The force that maintains the movement is called the centripetal force and it was directed towards the center of the circle.

We use Newton's second law.

F = m a

F = 43.5 m

whera m is the body mass.

D. Question what happens to the acceleration centripetal if we double the mass.

We assume that the force applied by the athlete remains constant, let's write Newton's second law.

F = ma a

a = F / m

the mass is

m = 2 m₀

we substitute

a = [tex]\frac{F}{2m_o}[/tex]

a = ½ a₀

a = 21.75 m / s²

we see that doubling the mass the acceleration is reduced by half.

In conclusion, using the cenripetal acceleration relations and Newton's second law we can find the results for the questions about the change in centripetal acceleration when changing the conditions of motion are:

A. The centripetal acceleration is: a = 43.5 m / s²

B. The radius is doubled, the centripetal acceleration is halved.

C. The force that creates the movement is called the centripetal force.

D. If the mass is doubled, the centripetal acceleration is halved.

Learn more here: brainly.com/question/6082363