Multiple-Concept Example 10 provides one model for solving this type of problem. Two wheels have the same mass and radius of 4.0 kg and 0.35 m, respectively. One has the shape of a hoop and the other the shape of a solid disk. The wheels start from rest and have a constant angular acceleration with respect to a rotational axis that is perpendicular to the plane of the wheel at its center. Each turns through an angle of 13 rad in 8.0 s. Find the net external torque that acts on each wheel.

Respuesta :

Newton's second law for rotational motion allows finding the net torque for each body is:

  • Ring torque is:   τ  = 0.199 Nm
  • Solid disc the torque is:   τ  = 0.995 N m

Newton's second law for rotational motion establishes a relationship between the torque, the moment of inertia, and the angular acceleration of the body.

 

               τ = I α

Where τ is the torque, I the moment of inertia and α the angular acceleration.

They indicate that the rotated angle is θ = 13 rad in a time of 8.0 s, let's use the rotational kinematics relations.

           θ = w₀ t + ½ α t²

The body starts from rest, therefore its inertial velocity is zero.

          θ = ½ α t²

          [tex]\alpha =\frac{2 \theta }{t^2}[/tex]  

Let's calculate

            α = [tex]\frac{2 \ 13^2}{8.0^2 }[/tex]

            α = 0.406 rad / s²

The moments of inertia of symmetrical bodies are tabulated:

  • Ring             I = m R²
  • Solid disc    I = ½ m R²

Let's look for every torque.

Ring

         τ = m R² α

         τ = 4.0 0.35² 0.406

         τ = 0.199 N m

          τ = ½ m R² α

          τ = ½ 4.0 0.35² 0.406

          τ = 0.0995 N m

In conclusion using Newton's second law for rotational motion we can find the net torque for each body is:

  • Ring torque is:   τ  = 0.199 Nm
  • Solid disc the torque is: τ  = 0.995 N m

Learn more about Newton's second law for rotation here:  brainly.com/question/15344745