Finding the sum of each outcome multiplied by it's respective probability, it is found that the expected value of guests in a room is of 1.85.
The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.
In this problem, the distribution is:
[tex]P(X = 1) = 0.35[/tex]
[tex]P(X = 2) = 0.5[/tex]
[tex]P(X = 3) = 0.1[/tex]
[tex]P(X = 4) = 0.05[/tex]
Hence:
[tex]E(X) = 0.35(1) + 0.5(2) + 0.1(3) + 0.05(4) = 1.85[/tex]
The expected value of guests in a room is of 1.85.
A similar problem is given at https://brainly.com/question/24855677
