We want to see how much must vary x so the argument of f(x) varies by 2 pi. We will see that x must vary (2π)/0.65.
So let's take the variation from 0 to 2π.
The argument is zero when x = 0
Argument = 0.65*x
if x = 0
Argument = 0.65*0 = 0
Now let's see which must be the value of x such that the argument is equal to 2π, so we must solve:
2π = 0.65*x
(2π)/0.65 = x
So we can see that x must vary from 0 to (2π)/0.65, or just a variation of (2π)/0.65.
If you want to learn more, you can read:
https://brainly.com/question/6904750
