The density of this gas mixture at 725 K and 6.13 atm is 21.68g/L.
How do we calculate density?
Density of the gas will be calculated by dividing the mass of gas by their volume.
For this first we have to calculate the volume of gas by using the ideal gas equation as:
PV = nRT, where
P = pressure = 6.13 atm
V = volume = to find?
R = universal gas constant = 0.08206 L.atm / mol.K
T = temperature = 725K
n is the moles of gas and it is mention that oxygen, nitrogen and argon have same moles and we let it be x, moles of this would be calculated from 149g as:
3x = 149 / (14+16+40) = 2.12
x = 0.709 moles
On putting all these values on the ideal gas equation, we get the value of V as:
V = (0.709)(0.082)(725) / 6.13 = 6.87 L
Now we consider the value to calculate the density as:
Density = 149 / 6.87 = 21.68g/L
Hence, the required density of mixture is 21.68g/L.
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