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Consider the line y = -6x + 9
Find the equation of the line that is perpendicular to this line and passes through the point (3, 6)

Find the equation of the line that is parallel to this line and passes through the point (3,6)

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Answer:

6x - y -12=0

Step-by-step explanation:

Given line ,

=> y = -6x + 9

On comparing to the slope intercept form ,

  • m = -6

The slope of the perpendicular line will be negative reciprocal of its slope , say m'

  • m' = 1/6

The given point is (3,6) . On using point Slope form of the line we have ,

=> x - 3 = 1/6 ( y - 6)

=> x - 3 = y/6 - 1

=> x -2 = y/6

=> 6x - 12 = y

=> 6x - y -12 = 0

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