The molarity of the base, Ca(OH)₂ needed for the reaction is 0.0689 M
We'll begin by writing the balanced equation for the reaction. This is given below:
Ca(OH)₂ + 2HCl —> CaCl₂ + 2H₂O
From the balanced equation above,
The mole ratio of the acid, HCl (nA) = 2
The mole ratio of the base, Ca(OH)₂ (nB) = 1
Volume of base, Ca(OH)₂ (Vb) = 25 mL
Volume of acid, HCl (Va) = 34.45 mL
Molarity of acid, HCl (Ma) = 0.1 M
The molarity of the base needed for the reaction can be obtained as follow:
MaVa / MbVb = nA / nB
(0.1 × 34.45) / (Mb × 25) = 2
3.445 / (Mb × 25) = 2
Cross multiply
Mb × 25 × 2 = 3.445
Mb × 50 = 3.445
Divide both side by 50
Mb = 3.445 / 50
Thus, the molarity of the base, Ca(OH)₂ needed for the reaction is 0.0689 M
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