Respuesta :
Testing the hypothesis, it is found that the appropriate test statistic is z = 0.54.
At the null hypothesis, it is tested if the proportion of women physics majors in your college is the same as the national average of 19%, that is:
[tex]H_0: p = 0.19[/tex]
At the alternative hypothesis, it is tested if the proportion is different, that is:
[tex]H_1: p \neq 0.19[/tex]
The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which:
- [tex]\overline{p}[/tex] is the sample proportion.
- p is the proportion tested at the null hypothesis.
- n is the sample size.
For this problem, the parameters are:
[tex]p = 0.19, n = 50, \overline{p} = \frac{11}{50} = 0.22[/tex]
Hence, the value of the test statistic is:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.22 - 0.19}{\sqrt{\frac{0.19(0.81)}{50}}}[/tex]
[tex]z = 0.54[/tex]
A similar problem is given at https://brainly.com/question/24166849
