Respuesta :
Answer:
0.50 moles KOH
Explanation:
Potassium hydroxide,
KOH
, will react with hydrochloric acid,
HCl
, to produce aqueous potassium chloride and water.
The balanced chemical equation that describes this neutralization reaction looks like this
KOH
(
a
q
)
+
HCl
(
a
q
)
→
KOH
(
a
q
)
+
H
2
O
(
l
)
So, the reaction consumes potassium hydroxide and hydrochloric acid in a
1
:
1
mole ratio, which implies that the number of moles of potassium hydroxide needed to completely neutralize the hydrochloric acid solution will be equal to the number of moles of hydrochloric acid present in said solution.
As you know, molarity tells you the number of moles of solute present in
1 L
=
10
3
mL
of solution.
This implies that the hydrochloric acid solution contains
500
.
mL
⋅
1.0 moles HCl
10
3
mL
=
0.50 moles HCl
Therefore, you can say that a complete neutralization requires
0.50
moles of potassium hydroxide. The answer is rounded to two sig figs, the number of sig figs you have for the molarity of the solution.
0.50 moles KOH
Explanation:
Potassium hydroxide,
KOH
, will react with hydrochloric acid,
HCl
, to produce aqueous potassium chloride and water.
The balanced chemical equation that describes this neutralization reaction looks like this
KOH
(
a
q
)
+
HCl
(
a
q
)
→
KOH
(
a
q
)
+
H
2
O
(
l
)
So, the reaction consumes potassium hydroxide and hydrochloric acid in a
1
:
1
mole ratio, which implies that the number of moles of potassium hydroxide needed to completely neutralize the hydrochloric acid solution will be equal to the number of moles of hydrochloric acid present in said solution.
As you know, molarity tells you the number of moles of solute present in
1 L
=
10
3
mL
of solution.
This implies that the hydrochloric acid solution contains
500
.
mL
⋅
1.0 moles HCl
10
3
mL
=
0.50 moles HCl
Therefore, you can say that a complete neutralization requires
0.50
moles of potassium hydroxide. The answer is rounded to two sig figs, the number of sig figs you have for the molarity of the solution.
801 g grams of KOH are needed to neutralize 10.2 mL of 0.14 M H C l in stomach acid.
What are moles?
A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Step 1: Data given
Volume of stomach acid (HCl) = 10.2 mL =.00102 L
Molarity HCl = 0.14 M
Step 2: The balanced equation:
[tex]KOH(aq)+HCl(aq)[/tex] → [tex]KOH(aq)+H_2O(l)[/tex]
For 1 mol of KOH, we need 1 mole of HCl to produce 1 mol of KOH and 1 mole of H2O
Step 3: Calculate moles of HCl
Moles HCl = molarity x volume
Moles HCl = 0.14 M x .00102 L
Moles HCl = 14.28 moles
Step 4: Calculate moles of KOH
For 1 mol of KOH, we need 1 mole of HCl to produce 1 mol of KOH and 1 mole of H2O
For 14.28 moles of HCl, we need 14.28 moles of KOH.
Step 5: Calculate the mass of KOH
Mass of KOH = moles x molar mass
Mass of KOH = 14.28 moles x 56.1056 g/mol
Mass of KOH = 801 g
Hence, 801 g grams of KOH are needed to neutralize 10.2 mL of 0.14 M HCl in stomach acid.
Learn more about moles here:
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