The given information on the diagram of the projector and the image can
be used to prove the congruency of the triangles.
∠ABD, ∠BDA, and side [tex]\overline {AD}[/tex] on ΔABD are congruent to ∠CBD, ∠BDC, and
segment [tex]\overline {CD}[/tex] on ΔCBD, therefore, ΔABD ≅ ΔCBD, by AAS Theorem
Reasons:
The figure of the projector that casts an image on the screen is attached.
The bisector of the line [tex]\overline {AC}[/tex] = [tex]\overline {BD}[/tex]
From the drawing, we have;
∠ABD ≅ ∠CBD by equal number arc mark.
The two column proof is therefore, presented as follows;
Statement [tex]{}[/tex] Reason
[tex]\overline {BD}[/tex] is perpendicular bisector of [tex]{}[/tex][tex]\overline {AC}[/tex] Given
[tex]\overline {AD}[/tex] = [tex]\overline {CD}[/tex] [tex]{}[/tex] Definition of bisected line [tex]\overline {AC}[/tex]
∠BDC = 90° [tex]{}[/tex] [tex]\overline {BD}[/tex] is perpendicular [tex]\overline {AC}[/tex]
∠BDA = 90° [tex]{}[/tex] [tex]\overline {BD}[/tex] is perpendicular [tex]\overline {AC}[/tex]
∠ABD ≅ ∠CBD [tex]{}[/tex] Given on the diagram
ΔABD ≅ ΔCBD [tex]{}[/tex] by Angle-Angle-Side AAS Congruency rule
The Angle-Angle-Side, AAS, Congruency postulate states that two
triangles are congruent where two adjacent angles and a non included side
on one triangle are congruent to the corresponding two adjacent angles
and a non included side on the other triangle.
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