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A car with a mass of 1500 kg is pulled by a rope that is horizontal to the ground. The tension in the rope is 2000 N and a friction force of 350 N opposes the car's motion. What is the magnitude of the car's acceleration?

Respuesta :

Answer:

Explanation:

Assuming the ground is level as well.

F = ma

a = F/m

a = (2000 - 350) / 1500

a = 1.1 m/s²

asuwafohjames

The acceleration of the car is 1.1 m/s².

To calculate the magnitude of the acceleration of the car, we use the formula below.

  • F-F' = ma................ Equation 1

Where:

  • F = Tension in the rope
  • F' = Friction force
  • m = mass of the car
  • a = acceleration of the car

Make a the subject of the equation

  • a = (F-F')/m................. Equation 2

From the equation,

Given:

  • F = 2000 N
  • F' = 350 N
  • m = 1500 kg

Substitute these values into equation 2

  • a = (2000-350)/1500
  • a = 1650/1500
  • a = 1.1 m/s²

Hence, the acceleration of the car is 1.1 m/s².

Learn more about acceleration here: https://brainly.com/question/605631

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