Using distance between two points, it is found that Jose traveled 25 units of length to football practice.
The distance between two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is given by:
[tex]D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
First, Jose goes from his house, at (-6,8), to Tyrell's house, at (6,8), thus:
[tex]D_1 = \sqrt{(6 - (-6))^2 + (8 - 8)^2} = \sqrt{12^2} = 12[/tex]
Then, he goes from Tyrell's house, at (6,8), to the football field, at (6, -5), thus:
[tex]D_2 = \sqrt{(6 - 6)^2 + (-5 - 8)^2} = \sqrt{13^2} = 13[/tex]
The total distance is:
[tex]D = D_1 + D_2 = 12 + 13 = 25[/tex]
Jose traveled 25 units of length to football practice.
A similar problem is given at https://brainly.com/question/22532602
