A class contributed $19.00 in quarters and dimes to a local homeless shelter. In
all there were 100 coins. How many were there of each kind.

Respuesta :

Answer: 60 quarters and 40 dimes

Step-by-step explanation:

Step 1: Setup Coin Value and Coin Total Equation:

Coin Value Equation → 0.1d + 0.25q = $19.00 where d = dimes and q = quarters

Coin Total Equation → d + q = 100

Step 2: Rearrange Coin Total Equation in terms of dimes (d)

d = 100 - q  ← Revised Coin Total Equation

Step 3: Plug in our Revised Coin Total Equation for d into our Coin Value Equation:

0.1(100 - q) + 0.25q = $19.00

0.1(100) - 0.1(q) + 0.25q = $19.00

10 - 0.1q + 0.25q = $19.00

10 + (0.25 - 0.1)q = $19.00

10 + 0.15q = $19.00

Step 4: Subtract 10 from each side of the equation to isolate q

10 - 10 + 0.15q = $19.00 - 10

0.15q = 9

Step 5: Divide each side of the equation by 0.15 to isolate q

0.15q/0.15  =    9/0.15

q = 60

Step 6: Using our value for q, Solve for d using our Coin Total Equation:

d + 60 = 100

Subtracting 60 from both sides, we get d + 60 - 60 = 100 - 60

d = 40

Summarizing our word problem, we see that 60 quarters and 40 dimes add up to $19.00