contestada


What is the equation of a line through point (-12,20) that is perpendicular to the line
with equation y=-6x + 4?

Respuesta :

Answer:      y =  ¹/₆ x + 22.

Step-by-step explanation:

Find the slope of the perpendicular line

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are negative-reciprocals of each other.

            ⇒  if the slope of one of the lines =  - 6

                 then the slope of the perpendicular line (m) = ¹/₆

Determine the equation

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

                              ⇒  y - 20 =  ¹/₆ (x - (-12))

                               ∴  y - 20 = ¹/₆ (x + 12)

We can also write the equation in the slope-intercept form (y=mx+c) like the equation in the question by making y the subject of the equation and expanding the bracket to simplify:

                          since   y - 20 = ¹/₆ (x + 12)

                                      y - 20 =  ¹/₆x + 2

                                              y =  ¹/₆x + 22

                             

∴ the slope-intercept equation of the perpendicular line is y =  ¹/₆ x + 22.

To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.

Ver imagen JoshEast