Respuesta :

kamilmatematik100504

[tex]\sf \large \boldsymbol {} 1) \ (4^0)^6= 4^{0\cdot 6}= 4^0\neq 4^6 \ False \\\\\\ 2) \ \dfrac{3^8}{3^{-2}} =3^{8-(-2)}=3^{8+2}=3^{10} \ \ True \\\\\\ 3) \ 2^{-5}\cdot 2^3=2^{-5+3}=2^{-2}=\dfrac{1}{2^2} \ \ True \\\\\\ 4) \ 6^4\cdot 3^4=(6\cdot 3)^4=18^4\neq 18^8 \ \ False[/tex]

Answer:

false, true, true, false

Step-by-step explanation:

(4^0)^6=1 is not equal to 4^6=4096

3^8/3^-2=59049 is equal to 3^10=59049

2^-5*2^3=0.25 is equal to 1/2^2=1/4=0.25

6^4*3^4=104976 is not equal to 18^8=11019960576

hope this helps!

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