Following are the solution to the given points:
Given:
[tex]\to mass(m)= 65\ kg\\\\\to h=10.0 \ m\\\\\to g=9.8 \ \frac{m}{s^2}[/tex]
To find:
gravitational potential energy(GPE)=?
kinetic energy(KE)=?
concept=?
v=?
Solution:
For point a:
[tex]\to GPE= mgh[/tex]
[tex]= 65 \times 10 \times 9.8\\\\ = 6370 \ J\\\\[/tex]
For point b:
[tex]\to KE=\frac{1}{2} m v^2\\\\[/tex]
[tex]=\frac{1}{2} \times 65 \times 14^2 \\\\=\frac{1}{2} \times 65 \times 14 \times 14 \\\\= 65 \times 14 \times 7 \\\\=6370\ J\\[/tex]
For point c:
As we've seen, there really is no force acting, and the mechanic KE: GPE is used. Because legitimate is conserved. Home energy loss means GPE must be equal to KE gain.
For point d:
A diver has risen 5 feet above the surface. As a result, according to the energy conservation law:
[tex]\to U_i + K_i= U_f + K_f\\\\ \to mg \times h + 0 = mg \times \frac{h}{2} + \frac{1}{2} m v^2\\\\ \to 9.8 \times 10 = 9.8 \times 5 + \frac{v^2}{2}\\\\\to 9.8 \times 10 - 9.8 \times 5 = \frac{v^2}{2}\\\\\to \frac{v^2}{2} =9.8( 10 - 5) \\\\\to v^2 =9.8( 10 - 5) \times 2 \\\\\to v^2 =9.8\times 5 \times 2 \\\\\to v^2 =98 \\\\\to v =98\ \frac{m}{s^2} \\\\[/tex]
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