Answer:
[tex]y=\displaystyle-\frac{4}{3}x+22[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
- Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept
- Parallel lines always have the same slope (m)
Determine the slope (m):
[tex]y=\displaystyle-\frac{4}{3}x -1[/tex]
The slope of the given line is [tex]\displaystyle-\frac{4}{3}[/tex], since it is in the place of m in y=mx+b. Because parallel lines always have the same slope, the slope of a parallel line would also be [tex]\displaystyle-\frac{4}{3}[/tex]. Plug this into y=mx+b:
[tex]y=\displaystyle-\frac{4}{3}x+b[/tex]
Determine the y-intercept (b):
[tex]y=\displaystyle-\frac{4}{3}x+b[/tex]
To find the y-intercept, plug in the given point (6,14) and solve for b:
[tex]14=\displaystyle-\frac{4}{3}(6)+b\\\\14=-8+b\\b=22[/tex]
Therefore, the y-intercept of the line is 22. Plug this back into [tex]y=\displaystyle-\frac{4}{3}x+b[/tex]:
[tex]y=\displaystyle-\frac{4}{3}x+22[/tex]
I hope this helps!
