Considering the zeros, the graph for the sinusoidal function is:
[tex]F(x) = \sin{\frac{\pi}{7}(x-3)}[/tex]
The sine function is given by:
[tex]F(x) = A\sin{Bx}[/tex]
In which:
In this problem:
[tex]\frac{2\pi}{B} = 14[/tex]
[tex]B = \frac{2\pi}{14}[/tex]
[tex]B = \frac{\pi}{7}[/tex]
Thus:
[tex]F(x) = \sin{\frac{\pi}{7}x}[/tex]
Like this, the zeros are at [tex]x = -14[/tex] and [tex]x = 0[/tex]. We want it at [tex]x = -11, x = 3[/tex], thus, we shift the function 3 units to the right, that is, the function is:
[tex]F(x) = \sin{\frac{\pi}{7}(x-3)}[/tex]
The graph is sketched at the end of this answer, and has the desired behavior, which are points (-11,0) and (3,0).
A similar problem is given at https://brainly.com/question/22136310