The curve above the graph of a sinusoidal function. It goes through the points (-11,0) and (3,0). Find a sinusoidal function that matches the given graph.if needed you can enter pi=3.1416… as pi in your answer otherwise use at least 3 decimal digits.
F(x)=

Respuesta :

Considering the zeros, the graph for the sinusoidal function is:

[tex]F(x) = \sin{\frac{\pi}{7}(x-3)}[/tex]

  • The zeros given for the function are: [tex]x = -11, x = 3[/tex].
  • For practicality, we are going to define a sine function, which has a zero at x = 0, so we use shifting.

The sine function is given by:

[tex]F(x) = A\sin{Bx}[/tex]

In which:

  • The amplitude is A.
  • The period is [tex]T = \frac{2\pi}{B}[/tex].

In this problem:

  • We suppose an amplitude of 1, thus [tex]A = 1[/tex].
  • The difference between the zeros is 14, so we use a period of 14, thus [tex]T = 14[/tex], and:

[tex]\frac{2\pi}{B} = 14[/tex]

[tex]B = \frac{2\pi}{14}[/tex]

[tex]B = \frac{\pi}{7}[/tex]

Thus:

[tex]F(x) = \sin{\frac{\pi}{7}x}[/tex]

Like this, the zeros are at [tex]x = -14[/tex] and [tex]x = 0[/tex]. We want it at [tex]x = -11, x = 3[/tex], thus, we shift the function 3 units to the right, that is, the function is:

[tex]F(x) = \sin{\frac{\pi}{7}(x-3)}[/tex]

The graph is sketched at the end of this answer, and has the desired behavior, which are points (-11,0) and (3,0).

A similar problem is given at https://brainly.com/question/22136310

Ver imagen joaobezerra