The coefficient of friction on the box sliding to the left is 0.3.
The given parameters;
- applied force , F = 36 N
- mass of the box, m = 12.2 kg
- velocity of the box, v = 2.6 m/s
The acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{36}{12.2} \\\\a = 2.95 \ m/s^2[/tex]
The coefficient of friction on the box is calculated as follows;
[tex]\mu_k = \frac{a}{g} \\\\\mu_k = \frac{2.95}{9.8} \\\\\mu_k = 0.3[/tex]
Thus, the coefficient of friction on the box is 0.3.
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