Answer: 15.9 m/s
Explanation:
KE = 1/2(mv^2)
190,000J = 1/2(3000kg)*v^2
1 J = 1 kg*m^2/s^2
190,000 kg*m^2/s^2 = 1/2(3000kg)*v^2
v^2 = (190,000 kg*m^2/s^2)/(1/2(3000kg))
v^2 = (190,000 kg*m^2/s^2)/(1500kg))
v^2 = 126.6667 m^2/s^2
v = 11.25 mm/s velocity of 3000kg vehicle
With the same kinetic energy, a vehicle of 1500kg would have a different velocity:
190,000 kg*m^2/s^2 = 1/2(1500kg)*v^2
190,000 kg*m^2/s^2 =(750kg)*v^2
v^2 = 253.33 m^2/s^2
v = 15.9 m/s