You deposit $9000 in an account that pays 5% interest compounded quarterly.

A. Find the value of one year

B.Use the future value formula for simple interest to determine the effective annual yield
(Formula: A=P(1 +rt)

Respuesta :

Step-by-step explanation:

Given:

  • Deposit P = $9000
  • Interest rate r = 5% = 0.05
  • Time t = 1 year
  • Number of compounds n = 4

A. Find the value of one year

  • [tex]A = P(1 + r/n)^{nt} = 9000(1+0.05/4)^4=9458.51[/tex]

B.  Use the future value formula for simple interest to determine the effective annual yield

  • [tex]A=P(1+rt)\\[/tex]
  • [tex]r=(A/P-1)/t[/tex]
  • [tex]r=(9458.51/9000-1)/1=0.0509[/tex]
  • r = 5.1%

Answer:

A)  $9458.51

B)  5.09%  (2 d.p.)

Step-by-step explanation:

Part A

Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = $9000
  • r = 5% = 0.05
  • n = 4 (quarterly)
  • t = 1 year

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=9000\left(1+\frac{0.05}{4}\right)^{4 \times 1}[/tex]

[tex]\implies \sf A=9000(1.0125)^4[/tex]

[tex]\implies \sf A=9458.508032...[/tex]

Therefore, the value of the account after 1 year is $9458.51.

Part B

Simple Interest Formula

A = P(1 + rt)

where:

  • A = final amount
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • A = $9458.51
  • P = $9000
  • t = 1 year

Substitute the given values into the formula and solve for r:

[tex]\implies \sf 9458.51=9000(1+r(1))[/tex]

[tex]\implies \sf 9458.51=9000(1+r)[/tex]

[tex]\implies \sf \dfrac{9458.51}{9000}=1+r[/tex]

[tex]\implies \sf r=\dfrac{9458.51}{9000}-1[/tex]

[tex]\implies \sf r=0.050945...[/tex]

[tex]\implies \sf r=5.0945... \%[/tex]

Therefore, the effective annual yield is 5.09% (2 d.p.).