The price of one adult ticket is $15 and the price of one child ticket is $8.
Two sets of equations can be derived from this question:
14a + 14c = 322 equation 1
12a + c = 188 equation 2
These equations are known as simultaneous equations and they can be solved to determine the cost of each ticket using the elimination method.
In order to determine the cost of the adult's ticket multiply equation 2 by 14
168a + 14c = 2632 equation 3
Subtract equation 1 from 3
2310 = 154a
Divide both sides by 154
a = $15
To determine the cost of the children's ticket substitute for a in equation 1
14(15) + 14c = 322
210 + 14c = 322
322 - 210 = 14c
112 = 14c
c = $8
To learn more about simultaneous equations, please check: brainly.com/question/23589883?referrer=searchResults
