kyleek190 kyleek190
  • 19-10-2021
  • Physics
contestada

How much power does it require to do 200 J of work in 5 s?

Respuesta :

phandar987
phandar987 phandar987
  • 29-10-2021

Answer:

soln

work done= 200J

Time taken = 5 sec

power=?

We know that,

power=w/t

= 2000/5

= 400W

Explanation:

hopw this will help you

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