Answer:
Step-by-step explanation:
1)
We know that if [tex]x^2=9[/tex], then [tex]x=\pm \sqrt{9}[/tex], so [tex]\boxed{x=3,-3}[/tex]
2)
We know that if [tex]x^3=8[/tex], then [tex]x=\sqrt[3]{8}[/tex], so [tex]\boxed{x=2}[/tex]
3)
[tex]x^3=\frac{1}{8}[/tex] means that [tex]x=\sqrt[3]{\frac{1}{8}}=\frac{\sqrt[3]{1}}{\sqrt[3]{8}}=\frac{1}{2}[/tex].
So, [tex]\boxed{x=\frac{1}{2}}[/tex].
4)
[tex]x^3=27[/tex] means that [tex]x=\sqrt[3]{27}=\sqrt[3]{3^3}=3[/tex].
So, [tex]\boxed{x=3}[/tex].
5)
[tex]x^2=25[/tex] means that [tex]x=\pm \sqrt{25}=\pm \sqrt{5^2}=\pm 5[/tex].
So, [tex]x=5,-5[/tex].
6)
We know that the side length of the square will be [tex]\sqrt{\frac{9}{16}}=\frac{\sqrt{9}}{\sqrt{16}}=\boxed{\frac{3}{4}}[/tex].
7)
[tex]6x^2=54[/tex] means that [tex]x^2=9[/tex], which means that [tex]\boxed{x=3,-3}[/tex].
8)
[tex]2x^2+25=75[/tex] means that [tex]2x^2=50[/tex], which means that [tex]x^2=25[/tex], which means that [tex]\boxed{x=5,-5}[/tex]
