Would you expect the spectrum of a blackbody radiator to have peaks and valleys like the spectrum of WF4-358? Why or why not? Define blackbody radiators in your answer.

Respuesta :

The Planck model for the black body and the emission spectrum of the atoms allows to find the results for the peaks in the spectrum of stars is:

  • The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.

The stars are very hot celestial bodies by nuclear fusion processes, in a good approximation they approximate an ideal body that absorbs or emits all the radiation called black body.

A black body is a cavity in thermal equilibrium at a dated temperature with a small hole, this hole is the so-called black body and its emission spectrum was explained by Planck, with the assumption that the energy is

             E = h νν

Where h is Planck's constant and ν is the frequency of the radiation. In the attachment we see the emission spectrum of a black body for various temperatures.

If in the material under study we have in addition the emission characteristics of some elements, it is energy appears as peaks in the emission spectrum and as black bands o valley in an absorption spectrum, therefore the existence of the structure is in a test of the existence of chemical elements within the stars.

In the attachment we can see the spectrum of a dwarf star where we can appreciate the spectrum of the black body and the emission and absorption lines of the chemical elements inside the star.

In conclusion using the Planck model for the black body and the emission spectra of the atoms we can find the results for the peaks in the spectrum of stars is:

  • The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.

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