Find the angle of C

Answer:
∠ C ≈ 22.6°
Step-by-step explanation:
Since Δ ABC is right at B
Using the sine ratio in the right triangle
sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{5}{13}[/tex] , then
∠ C = [tex]sin^{-1}[/tex] ( [tex]\frac{5}{13}[/tex] ) ≈ 22.6° ( to 1 dec. place )