An apple of 1 kg is dropped from 10.0m. How long does it take to hit the ground?
List the known and unknown quantities from the question.
u = initial velocity = 0 m/s
s = displacement = -10.0 m
g = acceleration due to gravity = -9.8 m/s²
t = time interval = ? s
Use the following kinematic equation.
s = ut + ½gt²
Since u = 0 m/s, ut = 0, and the equation can be rewritten.
s = ½gt²
Solve for t.
t² = 2s/g
t = √(2s/g)
t = √(2 × (-10.0 m))/(-9.8 m/s²)
t = √(-20.0 m)/(-9.8 m/s²) = 1.4 s
An apple of 8 kg is dropped from 10.0m. How long does it take to hit the ground?
mgh = 1/2×mv 2
wher m is the mass of the body v is velocity and g is acceleration due to gravity and h is the height
2gh=v 2
2×9.8×10 = v 2
v 2 = 196
v= 14m/s
T=v/g=1.4s
By any way you solve there is no role of mass here
It's gonna be 1.4 seconds always
