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The formula E =1/2 kx^2gives the potential energy E of a spring with spring constant k that has
been stretched by length x. Solve the formula fork to find the constant of a spring with a iven
potential energy and stretch.

Respuesta :

mhanifa

Answer:

  • [tex]k = 2E/x^2[/tex]

Step-by-step explanation:

Given formula:

  • [tex]E = 1/2kx^2[/tex]

To solve for k, multiply both sides by 2 and divide by x²:

  • [tex]2E=kx^2[/tex]
  • [tex]k = 2E/x^2[/tex]
Sᴘᴀᴄᴇ7

Answer:

[tex]\sf\longmapsto \: k = \frac{2E}{x {}^{2} } [/tex]

Step-by-step explanation:

The formula given is :

[tex]\sf\longmapsto \: E = \frac{1}{2} kx²[/tex]

Now, multiply (×) both sides by 2 and divide (÷) by x^2

[tex]\sf\longmapsto \: 2E = kx²[/tex]

[tex]\sf\longmapsto \: k = \frac{2E}{x {}^{2} } [/tex]

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