Respuesta :
Answer:
Step-by-step explanation:
Answer: Yes, [tex]\frac{x}{7}[/tex] is equivalent to [tex]\frac{1}{7} x[/tex].
Answer:
No, x = 1 and x = -1
Step-by-step explanation:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
x/7-(1/(7*x))=0
Simplify 1/7x
Equation at the end of step
1
:
x/7-1/7x
= 0
7 7x
STEP
2
:
x
Simplify —
7
Equation at the end of step
2
:
x 1
— - —— = 0
7 7x
STEP
3
:
Calculating the Least Common Multiple :
3.1 Find the Least Common Multiple
The left denominator is : 7
The right denominator is : 7x
Number of times each prime factor
appears in the factorization of:
Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right}
7 1 1 1
Product of all
Prime Factors 7 7 7
Number of times each Algebraic Factor
appears in the factorization of:
Algebraic
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right}
x 0 1 1
Least Common Multiple:
7x
Calculating Multipliers :
3.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = x
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
3.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. x • x
—————————————————— = —————
L.C.M 7x
R. Mult. • R. Num. 1
—————————————————— = ——
L.C.M 7x
Adding fractions that have a common denominator :
3.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x • x - (1) x2 - 1
——————————— = ——————
7x 7x
Trying to factor as a Difference of Squares:
3.5 Factoring: x2 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 1 is the square of 1
Check : x2 is the square of x1
Factorization is : (x + 1) • (x - 1)
Equation at the end of step
3
:
(x + 1) • (x - 1)
————————————————— = 0
7x
STEP
4
:
When a fraction equals zero :
4.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
(x+1)•(x-1)
——————————— • 7x = 0 • 7x
7x
Now, on the left hand side, the 7x cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
(x+1) • (x-1) = 0
Theory - Roots of a product :
4.2 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation:
4.3 Solve : x+1 = 0
Subtract 1 from both sides of the equation :
x = -1
Solving a Single Variable Equation:
4.4 Solve : x-1 = 0
Add 1 to both sides of the equation :
x = 1
Two solutions were found :
x = 1
x = -1
