No, the downward force along the plane is 11 N and the maximum static friction force is 12 N.
The normal force on the block is calculated as follows;
Fₙ = Wcosθ
Fₙ = 36 x cos(18)
Fₙ = 34.24 N
The minimum force required to move the block is calculated as;
[tex]F_s = u_s \times F_n\\\\F_s = 0.35 \times 34.24\\\\F_s = 12 \ N[/tex]
The parallel force on the block along the plane is calculated as;
[tex]F = W sin(\theta) \\\\F = (36 \times sin(18))\\\\F = 11 \ N[/tex]
Thus, we can conclude that the block will not slide since the parallel force along the plane is less than the maximum static friction.
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