Respuesta :
Answer:
Option C [tex]60.75\ cm^{3}[/tex]
Step-by-step explanation:
Let
x------> the volume of the small container
y------> the volume of the large container
z-----> the scale factor
we know that
The volume of the small container is equal to the scale factor elevated to the cube multiplied by the volume of the large container
so
[tex]x=z^{3}y[/tex]
In this problem we have
[tex]z=0.075, y=144,000\ cm^{3}[/tex]
substitute
[tex]x=0.075^{3}(144,000)=60.75\ cm^{3}[/tex]