The distance between two points is 6_/6.One endpoint is (4,-1). It is known that the y-coordinate of the other endpoint is 9.
What is the x-coordinate of this endpoint?
Drag the values into the box to correctly complete the table.

Possible x-coordinate of endpoint =

Choices:
12
-4
8
4+2_/29
2_/29
4-2_/29

Respuesta :

The x-coordinate of the given endpoint will be "[tex]x = 4 \pm 2\sqrt{29}[/tex]".

According to the question,

The end points are:

  • [tex](x_1,y_1) = (4,-1)[/tex]
  • [tex](x_2, y_2) = (x,9)[/tex]

Distance,

  • [tex]6\sqrt{6}[/tex]

As we know,

The distance formula,

→ [tex]Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

By substituting the values, we get

→         [tex]6\sqrt{6} = \sqrt{(x-4)^2+(9+1)^2}[/tex]

→          [tex]216= (x-4)^2+100[/tex]

→   [tex](x-4)^2 = 116[/tex]

→       [tex]x-4 = \pm \sqrt{116}[/tex]

→       [tex]x-4=\pm 2\sqrt{29}[/tex]

→             [tex]x = 4 \pm 2\sqrt{29}[/tex]                

Thus the above answer is right.  

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