The x-coordinate of the given endpoint will be "[tex]x = 4 \pm 2\sqrt{29}[/tex]".
According to the question,
The end points are:
Distance,
As we know,
The distance formula,
→ [tex]Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
By substituting the values, we get
→ [tex]6\sqrt{6} = \sqrt{(x-4)^2+(9+1)^2}[/tex]
→ [tex]216= (x-4)^2+100[/tex]
→ [tex](x-4)^2 = 116[/tex]
→ [tex]x-4 = \pm \sqrt{116}[/tex]
→ [tex]x-4=\pm 2\sqrt{29}[/tex]
→ [tex]x = 4 \pm 2\sqrt{29}[/tex]
Thus the above answer is right.
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