The speed the ball was projected upwards is 29.7 m/s.
The given parameters;
- height in which the ball was thrown, h = 20 m
- distance traveled by the ball, X = 60 m
The time of motion of the ball to travel to the given height is calculated as;
[tex]h = v_0_yt - \frac{1}{2} gt^2\\\\-20 = 0 - 0.5\times 9.8t^2\\\\-20 = -4.9t^2\\\\t^2 = \frac{20}{4.9} \\\\t^2 = 4.08\\\\t = \sqrt{4.08} \\\\t = 2.02\ s[/tex]
The horizontal speed in which the ball was projected upwards is calculate as;
X = (v₀ₓ)t
60 = 2.02v₀ₓ
[tex]v_0_x = \frac{60}{2.02} \\\\v_0_x = 29.7 \ m/s[/tex]
Thus, the speed the ball was projected upwards is 29.7 m/s.
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