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A ball rolls off a level table with a speed of 2.2 m/s. The table is 1.2 meters high. How far away from the base of the table does the ball land?

Respuesta :

Cricetus

The base of table is "1.08856 m" far away from the ball land.

Given:

Distance travelled by ball,

  • S = 1.2 m

Initial velocity,

  • u = 0 m/s

Acceleration,

  • a = 9.8 m/s²

Constant speed,

  • 2.2 m/s

As we know the formula,

→ [tex]S = ut+\frac{1}{2}at^2[/tex]

By substituting the values, we get

→ [tex]1.2=\frac{1}{2}\times 9.8t^2[/tex]

→ [tex]1.2 = 4.9 t^2[/tex]

→    [tex]t = \sqrt{\frac{1.2}{4.9} }[/tex]

→      [tex]= 0.4948 \ seconds[/tex]

Let,

  • Horizontal distance will be "x".
  • Time = t

→ [tex]x = 2.2\times t[/tex]

     [tex]= 2.2\times 0.4948[/tex]

     [tex]= 1.08856 \ m[/tex]

Thus the solution above is right.

Learn more:

https://brainly.com/question/19170664

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