In Young’s two slit experiment, the first dark fringe above the central bright fringe occurs at an angle of 0.44˚. What is the ratio of the slit separation, d, to the wavelength of the light, λ

Respuesta :

Answer:

d / λ = 26.7

Explanation:

In Young's double slit experiment, constructive interference is described by the expression

   d sin θ = m λ

In the case of destructive interference we must add half wavelength (λ/2)

   d siyn θ = (m + ½) λ

Let's clear

    d / λ = (m + ½) / sin θ

Let's calculate

   d / λ = (2+ ½) / sin 5.4

   d / λ = 5 / (2 sin 5.4)

   d / λ = 26.7

The ratio of the slit separation, d, to the wavelength of the light, λ will be 26.7.

What is wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The expression for the constructive interference is given as;

[tex]\rm d sin\theta= m \lambda[/tex]

For the destructive interference;

[tex]dsin \theta = (m+\frac{1}{2} )\lambda \\\\ \frac{d}{\lambda} =\frac{ (m+\frac{1}{2} )}{ sin \theta} \\\\ \frac{d}{\lambda} =\frac{(2+\frac{1}{2}) }{sin 5.4^0} \\\\ \frac{d}{\lambda} =26.7[/tex]

Hence the ratio of the slit separation, d, to the wavelength of the light, λ will be 26.7.

To learn more about the wavelength refer to the link;

brainly.com/question/7143261