PLS HELP Given the following table with selected values of the linear functions g(x) and h(x), determine the x-intercept of g(h(x)).
x –6 –4 –1 1 5
g(x) 16 10 1 –5 –17
h(x) –11 –7 –1 3 11
A. -5
B. -5/6
C. 5/6
D. 5

Respuesta :

Using linear and composite functions, it is found that the x-intercept of g(h(x)) is [tex]x = -\frac{5}{6}[/tex], given by option B.

-------------------------------

The equation of a line is:

[tex]y = mx + b[/tex]

In which:

  • m is the slope.
  • b is the y-intercept.

Function g:

  • Two of the points are (-6,16) and (-4,10).
  • The slope is given by change in y divided by change in x, thus:

[tex]m = \frac{10 - 16}{-4 - (-6)} = -3[/tex]

Thus:

[tex]g(x) = -3x + b[/tex]

Point (-4,10) means that when [tex]x = -4, g(x) = 10[/tex], and we use this to find b, so:

[tex]10 = -3(-4) + b[/tex]

[tex]12 + b = 10[/tex]

[tex]b = -2[/tex]

Then

[tex]g(x) = -3x - 2[/tex]

Function h:

  • Two of the points are (-6,-11) and (-4,-7).
  • The slope is:

[tex]m = \frac{-7 - (-11)}{-4 - (-6)} = \frac{4}{2} = 2[/tex]

Thus:

[tex]h(x) = 2x + b[/tex]

Point (-4,-7) means that when [tex]x = -4, h(x) = -7[/tex], and we use this to find b, so:

[tex]-7 = 2(-4) + b[/tex]

[tex]-8 + b = -7[/tex]

[tex]b = 1[/tex]

Then

[tex]h(x) = 2x + 1[/tex]

The composite function is:

[tex]g(h(x)) = g(2x + 1) = -3(2x + 1) - 2 = -6x - 3 - 2 = -6x - 5[/tex]

The x-intercept it the zero of the function, thus:

[tex]-6x - 5 = 0[/tex]

[tex]6x = -5[/tex]

[tex]x = -\frac{5}{6}[/tex]

Which is option B.

A similar problem is given at https://brainly.com/question/21010520

Answer:

-5/6

Step-by-step explanation: