[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]
- Determine the surface area of the right square pyramid.
[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]
The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where
- b = base of the right square pyramid
- l = slant height of the right square pyramid.
In the given figure,
- base (b) = 4 ft.
- slant height (l) = 8 ft.
Now, let's substitute the values of b & l in the formula & solve it :-
[tex] \sf \: {b}^{2} + 2bl \\ = \sf \: {4}^{2} + 2 \times 4 \times 8 \\ = \sf \: 16 + 8 \times 8 \\ = \sf \: 16 + 64 \\ = \huge\boxed{\boxed{ \bf 80 \: ft ^{2} }}[/tex]
So, the surface area of the right square pyramid is 80 ft².
