contestada

The length of a rectangle is four more than double the width. If the perimeter is 110 inches, find the
dimensions.
The width is
inches.
The length is
inches.

Respuesta :

Lanuel

The dimensions of the rectangle are 38 and 17 inches respectively.

  • Let the length of the rectangle be L.
  • Let the width of the rectangle be W.

Given the following data:

  • Perimeter of rectangle = 110 inches

Translating the word problem into an algebraic equation, we have;

[tex]L = 2W + 4[/tex]

To find the dimensions of the rectangle;

Mathematically, the perimeter of a rectangle is calculated by using the formula;

[tex]P = 2(L + W)[/tex]

Substituting the values;

[tex]110 = 2([2W + 4] + W)\\\\110 = 2(2W + 4 + W)\\\\110 = 2(3W + 4)\\\\110 = 6W + 8\\\\6W = 110 - 8\\\\6W = 102\\\\W = \frac{102}{6}[/tex]

Width, W = 17 inches.

Next, we would find the length;

[tex]L = 2(17) + 4\\\\L = 34 + 4[/tex]

Length, L = 38 inches.

Find more information: brainly.com/question/897975

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