Answer:
y = 2x
Step-by-step explanation:
We have,
Equation for a line
[tex] \boxed{ \mathfrak{ \blue{y = mx + c}} } [/tex]
m is the slope and c the y intercept.
the intercept made on the y-axis is 0
therefore c = 0
now, we need to get to the value of m
for this we take any two points that lie on the line.
looking at the graph I see one such point is (0,0) while the other being (1, 2).
for two points A(x, y) and B(p, q):-
[tex] \boxed{\mathsf{m = \frac{q - y}{p - x} }} [/tex]
here the two points A and B are (0, 0) and (1, 2)
therefore,
[tex] \mathsf{m = \frac{2 - 0}{1 - 0} } [/tex]
[tex] \mathsf{m = \frac{2}{1} } [/tex]
therefore, m = 2
now, we'll simply put the values in their place
y =2x + 0
we get the equation for the given line
y = 2x
