The number of moles of O2 that would be required to generate 13.0 mol of NO2 in the reaction at 60.6% reaction yield would be 10.73 moles.
From the balanced equation of the reaction:
[tex]2 NO (g) + O_2 (g) ---> 2 NO_2 (g)[/tex]
The ratio of O2 to NO2 is 1:2
Thus, if 13 moles of NO2 is to be generated, then 6.5 moles of O2 would be needed.
However, the reaction is 60.6% yield. So, we assume that 6.5 moles of O2 is for 60.6% yield.
If 60.6% = 6.5 moles, then 100% would be:
= 6.5 x 100/60.6
= 10.73 moles
More on mole ratio can be found here: https://brainly.com/question/15288923
