Answer:
the other two factors, (2x+1)(3x+1)
Step-by-step explanation:
(a + 1)x³ + (2 – 3a)x² – (3a – 1)x + 2a – 13 = 0 ...(1)
x-3 = 0 x = 3
(a + 1)*3³ + (2 – 3a)*3² – (3a – 1)*3 + 2a – 13 = 0
-7a + 35 = 0
a = 5 .. substitute to (1)
6x³ -13x² – 14x -3 = 0
(x-3)(6x²+px+1) = 0 ..... 1*x * 6x² = 6x³, -3 * 1 = -3
6x³ +(p-18)x² +(1-3p)x -3 = 0
p-18 = -13
p = 5
6x²+5x+1 = (2x+1)(3x+1)
