Respuesta :
The minimum number of pens that can be in Jake's drawer is 70 pens.
we can do like this
3:4
add them
3+4=7, not over 70
hmm
one way is
3+4=7
how many 7's are more than 40
7x>40
divide both sides by 7
x>5.7
about 6
3*6=18
4*6=24
18:24 is the minimum ratio
18+24=42
minimum number of pens is 42
3:4
add them
3+4=7, not over 70
hmm
one way is
3+4=7
how many 7's are more than 40
7x>40
divide both sides by 7
x>5.7
about 6
3*6=18
4*6=24
18:24 is the minimum ratio
18+24=42
minimum number of pens is 42