The molecular formula of the compound is [tex]C_3H_6O_3[/tex]
Given the following
The empirical formula of a compound = CH₂O
Molecular formula = 90g/mol
To get the molecular formula, then;
[tex](CH_2O)_n=90\\[/tex]
Calculate the value of "n"
[tex](CH_2O)_n=90\\(12+ 2(1)+16)_n=90\\30n=90\\n=\frac{90}{30}\\n=3[/tex]
Get the molecular formula:
[tex]=(CH_2O)_3\\=C_3(H_2)_3O_3\\=C_3H_6O_3[/tex]
Hence the molecular formula of the compound is [tex]C_3H_6O_3[/tex]
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