The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate parameter of 7.6% per hour. How many hours does it take for the size of the sample to double?
Set the growth factor equal to 2 [tex]e^{.076 t} = 2[/tex] Solve for t, Take natural log of both sides [tex]ln (e^{.076 t}) = ln(2) \\ .076 t = ln(2) \\ ........ \\ t = \frac{ln (2)}{.076}[/tex]
