Respuesta :

Space

Answer:

[tex]\displaystyle f'(0.3) = \arccos (0.3)[/tex]

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Integration

  • Integrals

Integration Rule [Fundamental Theorem of Calculus 2]:                                     [tex]\displaystyle \frac{d}{dx}[\int\limits^x_a {f(t)} \, dt] = f(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f(x) = \int\limits^x_0 {\arccos (t)} \, dt[/tex]

Step 2: Differentiate

  1. Integration Rule [Fundamental Theorem of Calculus 2]:                           [tex]\displaystyle f'(x) = \arccos (x)[/tex]

Step 3: Evaluate

  1. Substitute in x [Function]:                                                                             [tex]\displaystyle f'(0.3) = \arccos (0.3)[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration