contestada

A spray paint can with a pressure of 2.50 atm is trapped inside a burning
factory. Its initial temperature is 25°C. What is the final pressure of the can
if the fire reaches a temperature of 635°C? Assume that the volume of the
can remains constant!

Respuesta :

First convert Temperatures to Kelvin scale

  • 25°C=25+273=298K
  • 635°C=635+273=908K

Now

  • P_1=2.5atm
  • T_1=298K
  • T_2=908K

USING GAY LUSSAC's Law

[tex]\\ \sf\longmapsto P_1T_2=P_2T_1[/tex]

[tex]\\ \sf\longmapsto P_2=\dfrac{P_1T_2}{T_1}[/tex]

[tex]\\ \sf\longmapsto P_2=\dfrac{2.5(298)}{25}[/tex]

[tex]\\ \sf\longmapsto P_2=\dfrac{795}{25}[/tex]

[tex]\\ \sf\longmapsto P_2=31.8atm[/tex]