Answer:
The factor of [tex]-4+8a-4a^2[/tex] is [tex]-4(a-1)^2[/tex]
A is correct.
Step-by-step explanation:
Given: [tex]-4+8a-4a^2[/tex]
We need to factor the trinomial.
First we will take common factor from each term.
[tex]\Rightarrow -4\cdot 1-4\cdot -2a-4\cdot a^2[/tex]
Take out -4 common
[tex]\Rightarrow -4(1-2a+a^2)[/tex]
Using formula of perfect square.
[tex]x^2-2xy+y^2=(x-y)^2[/tex]
[tex]\Rightarrow -4(a-1)^2[/tex]
Hence, The factor of [tex]-4+8a-4a^2[/tex] is [tex]-4(a-1)^2[/tex]
